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CH3041
pE AND pE0
                Ox + ne-  ®  Red        Eo1/2 
Using activities:        K1/2 = {Red} / ({Ox} {e-}n)
Þ {e-}n = {Red}/({Ox} K1/2) Using Laws of Logs:
pE =1/n log K1/2 -1/n log {Red}/{Ox} = -log{e-}
pE =     pEo         - 1/n log {Red} / {Ox}
• pEo = 1/n log K1/2 =  Eo1/2 / 0.0591
• The Nernst Equation for a half reaction in
   the pE form is :  (concs. for convenience)
   pE = pEo - 1/n log ([Red] / [Ox])      at 25oC